literal 0 in replace string after group substitution

[4EverMaAT]

find

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^(RepeatableText=)(.*)$

replace

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$1

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0

but it is written as $10

and the replace text is written as $10 instead of $1 being the first group, followed by a literal 0


Any ideas?

[DigitalVolcano]

Try-

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${1}0

Putting the curly brackets round the number separates it from the following literals.

[4EverMaAT]

Try-

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${1}0

Putting the curly brackets round the number separates it from the following literals.

I will remember that next time. I ended up doing

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$1 0 

(a space between the $1 group and literal 0)

And then added a separate non-regex search into the batch for

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RepeatableText= 0

(now a space between = and 0 from previous search/replace operation)

and replace with

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RepeatableText=0

(Removing the literal space after =)

That is what I liked about your software. I didn't have to drive myself crazy for 10 hours trying to make it perfectly efficient search. I just did it the crude way and it still worked out ok. But now I know also the more efficient way.